Thursday, September 3, 2015

Making a Reverse Log Pot from a Linear Pot

I need a 10k reverse log pot for the Drive Pot of the Roger Mayer Octavia. I decided to make one out of at linear pot and bridging lug 1&2 to lug 3 with a resistor. I made the calculation as below using http://www.sengpielaudio.com/calculator-paralresist.htm

Rtotal = R1×R2/(R1+R2)

The curve is for using a 50K linear pot with a 12k resistor.























Below is my build. the 10k resistor is connected to pot 3=>pot1&2.
pot 3 will be ground.


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